3600+x^2-150x=0

Solution for 3600+x^2-150x=0 equation:

3600+x^2-150x=0

a = 1; b = -150; c = +3600;
Δ = b2-4ac
Δ = -1502-4·1·3600
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8100}=90$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-90}{2*1}=\frac{60}{2}
=30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+90}{2*1}=\frac{240}{2}
=120
$